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Multiplying the fraction by $x+1$
Learn how to solve polynomial long division problems step by step online.
$\frac{\frac{\left(x^2+5x+6\right)\left(x^2+2x-3\right)\left(x+1\right)}{\left(x^2-1\right)\left(3x+6\right)}}{-x^2+6x-9}$
Learn how to solve polynomial long division problems step by step online. Simplify the expression (((x^2+5x+6)/(x^2-1)(x^2+2x+-3))/(3x+6)(x+1))/(-x^2+6x+-9). Multiplying the fraction by x+1. Divide fractions \frac{\frac{\left(x^2+5x+6\right)\left(x^2+2x-3\right)\left(x+1\right)}{\left(x^2-1\right)\left(3x+6\right)}}{-x^2+6x-9} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}. The trinomial \left(-x^2+6x-9\right) is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula.