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$\int\frac{x^2+3x-4}{x^2-2x-8}dx$
Learn how to solve integral calculus problems step by step online. Integrate the function (x^2+3x+-4)/(x^2-2x+-8). Find the integral. Divide x^2+3x-4 by x^2-2x-8. Resulting polynomial. Expand the integral \int\left(1+\frac{5x+4}{x^2-2x-8}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately.