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$\int\left(\frac{x^2+3x}{x+4}+\frac{-\left(16+3x\right)}{x+4}\right)dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (x^2+3x)/(x+4)+(-(16+3x))/(x+4). Find the integral. Simplify the expression inside the integral. The integral \int\frac{x^2+3x}{x+4}dx results in: \frac{1}{2}x^2-x+4\ln\left(x+4\right). Gather the results of all integrals.