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Find the derivative of $\frac{x^{\left(2y-3\right)}x^{\left(y+5\right)}}{x^{\left(3y+1\right)}x^{\left(y-3\right)}}$

Step-by-step Solution

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Final answer to the problem

$\frac{x^{\left(-1+7y\right)}\left(2+3x^{\left(2+3y\right)}\right)\left(1-4x^{\left(-2+4y\right)}\ln\left(x\right)\right)+\left(2x^{\left(-3+4y\right)}-4x^{\left(-5+8y\right)}\right)x^{\left(2+3y\right)}\left(1-3x^{\left(2+3y\right)}\ln\left(x\right)\right)}{\left(1-3x^{\left(2+3y\right)}\ln\left(x\right)\right)\left(1-4x^{\left(-2+4y\right)}\ln\left(x\right)\right)\left(x^{\left(-2+4y\right)}\right)^2}$
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Step-by-step Solution

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Simplifying

$\frac{d}{dx}\left(\frac{x^{\left(2+3y\right)}}{x^{\left(-2+4y\right)}}\right)$

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$\frac{d}{dx}\left(\frac{x^{\left(2+3y\right)}}{x^{\left(-2+4y\right)}}\right)$

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Learn how to solve problems step by step online. Find the derivative of (x^(2y-3)x^(y+5))/(x^(3y+1)x^(y-3)). Simplifying. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. The derivative \frac{d}{dx}\left(x^{\left(2+3y\right)}\right) results in \frac{\left(2+3x^{\left(2+3y\right)}\right)x^{\left(1+3y\right)}}{1-3x^{\left(2+3y\right)}\ln\left(x\right)}. The derivative \frac{d}{dx}\left(x^{\left(-2+4y\right)}\right) results in \frac{2\left(-1+2x^{\left(-2+4y\right)}\right)x^{\left(-3+4y\right)}}{1-4x^{\left(-2+4y\right)}\ln\left(x\right)}.

Final answer to the problem

$\frac{x^{\left(-1+7y\right)}\left(2+3x^{\left(2+3y\right)}\right)\left(1-4x^{\left(-2+4y\right)}\ln\left(x\right)\right)+\left(2x^{\left(-3+4y\right)}-4x^{\left(-5+8y\right)}\right)x^{\left(2+3y\right)}\left(1-3x^{\left(2+3y\right)}\ln\left(x\right)\right)}{\left(1-3x^{\left(2+3y\right)}\ln\left(x\right)\right)\left(1-4x^{\left(-2+4y\right)}\ln\left(x\right)\right)\left(x^{\left(-2+4y\right)}\right)^2}$

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Function Plot

Plotting: $\frac{x^{\left(-1+7y\right)}\left(2+3x^{\left(2+3y\right)}\right)\left(1-4x^{\left(-2+4y\right)}\ln\left(x\right)\right)+\left(2x^{\left(-3+4y\right)}-4x^{\left(-5+8y\right)}\right)x^{\left(2+3y\right)}\left(1-3x^{\left(2+3y\right)}\ln\left(x\right)\right)}{\left(1-3x^{\left(2+3y\right)}\ln\left(x\right)\right)\left(1-4x^{\left(-2+4y\right)}\ln\left(x\right)\right)\left(x^{\left(-2+4y\right)}\right)^2}$

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a
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x
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.
(◻)
+
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◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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