The quotient of powers of same base ($\frac{e^{\frac{2}{3}x}}{e^{\frac{5}{2}x}}$) can be rewritten as the base to the power of the difference of the exponents
$e^{-\frac{11}{6}x}$
Final answer to the problem
$e^{-\frac{11}{6}x}$
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