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Find the derivative of $\sqrt{x}e^{\left(x^2\right)}\left(x^2+1\right)^4$

Step-by-step Solution

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Final answer to the problem

$\frac{e^{\left(x^2\right)}\left(x^2+1\right)^{3}\left(21x^2+1+4x^{4}\right)}{2\sqrt{x}}$
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Step-by-step Solution

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  • Find the derivative using the definition
  • Find the derivative using the product rule
  • Find the derivative using the quotient rule
  • Find the derivative using logarithmic differentiation
  • Find the derivative
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
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1

Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$

$\frac{d}{dx}\left(\sqrt{x}\right)e^{\left(x^2\right)}\left(x^2+1\right)^4+\sqrt{x}\left(\frac{d}{dx}\left(e^{\left(x^2\right)}\right)\left(x^2+1\right)^4+e^{\left(x^2\right)}\frac{d}{dx}\left(\left(x^2+1\right)^4\right)\right)$

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$\frac{d}{dx}\left(\sqrt{x}\right)e^{\left(x^2\right)}\left(x^2+1\right)^4+\sqrt{x}\left(\frac{d}{dx}\left(e^{\left(x^2\right)}\right)\left(x^2+1\right)^4+e^{\left(x^2\right)}\frac{d}{dx}\left(\left(x^2+1\right)^4\right)\right)$

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Learn how to solve equations problems step by step online. Find the derivative of x^1/2e^x^2(x^2+1)^4. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g'. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}. Applying the derivative of the exponential function.

Final answer to the problem

$\frac{e^{\left(x^2\right)}\left(x^2+1\right)^{3}\left(21x^2+1+4x^{4}\right)}{2\sqrt{x}}$

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Function Plot

Plotting: $\frac{e^{\left(x^2\right)}\left(x^2+1\right)^{3}\left(21x^2+1+4x^{4}\right)}{2\sqrt{x}}$

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2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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