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Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$, where $f=
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$\frac{d}{dx}\left(\sqrt{\frac{v}{p}}\right)\left(1+\frac{-abc}{x^2}\right)+\sqrt{\frac{v}{p}}\frac{d}{dx}\left(1+\frac{-abc}{x^2}\right)$
Learn how to solve problems step by step online. Find the derivative using the product rule d/dx((v/p)^1/2(1+(-abc)/(x^2))). Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=. The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. The derivative of the constant function (\frac{\sqrt{v}}{\sqrt{p}}) is equal to zero.