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Find the derivative of $\frac{1}{\sqrt[3]{x}}+\frac{-1}{x^3}+\frac{3}{\left(2x+1\right)^3}$ using the definition

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 Solution

 Videos

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Calculus - Derivative of inverse function given an equation, f(x) = x^3 + 7x; Find g'(8)

https://www.youtube.com/watch?v=cPvUjcS7N9w

Calculus - How find the first derivative using a chart, 1/f(x) at x=1

https://www.youtube.com/watch?v=V5OROgIBnDc

Algebra 2 - How to find the real zero of a cubic function, y = -1(x - 3)^3 + 1

https://www.youtube.com/watch?v=4dSA02Fzric

Calculus - Learn how to take derivative using quotient rule by simplifying first, f(x)=x(1- 4/(x+3))

https://www.youtube.com/watch?v=Mqjiw5Ax_4w

Calculus - Use quotient rule to take derivative with trigonometric functions, y=(1-cosx)/sinx

https://www.youtube.com/watch?v=BAa7KHPk7bA

 Main Topic: Definition of Derivative

Resolution of derivatives using the definition of the derivative, which is the limit of difference quotients of real numbers.

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Definition of Derivative

Find the derivative of $\frac{1}{\sqrt[3]{x}}+\frac{-1}{x^3}+\frac{3}{\left(2x+1\right)^3}$ using the definition

Related Videos

 Solution

 Videos

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

Calculus - Derivative of inverse function given an equation, f(x) = x^3 + 7x; Find g'(8)

Calculus - How find the first derivative using a chart, 1/f(x) at x=1

Algebra 2 - How to find the real zero of a cubic function, y = -1(x - 3)^3 + 1

Calculus - Learn how to take derivative using quotient rule by simplifying first, f(x)=x(1- 4/(x+3))

Calculus - Use quotient rule to take derivative with trigonometric functions, y=(1-cosx)/sinx

Similar Problems Solved

 Main Topic: Definition of Derivative

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