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$\int\frac{9x^3-4x^2+30x-10}{x+3}dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (9x^3-4x^230x+-10)/(x+3). Find the integral. Divide 9x^3-4x^2+30x-10 by x+3. Resulting polynomial. Expand the integral \int\left(9x^{2}-31x+123+\frac{-379}{x+3}\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately.