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$\int\frac{9-t^2}{t-3}dt$
Learn how to solve integral calculus problems step by step online. Find the integral of (9-t^2)/(t-3). Find the integral. Rewrite the expression \frac{9-t^2}{t-3} inside the integral in factored form. The integral of a function times a constant (-1) is equal to the constant times the integral of the function. Expand the integral \int\left(3+t\right)dt into 2 integrals using the sum rule for integrals, to then solve each integral separately.