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$\int\frac{8x^5-3x^2-1}{x-1}dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (8x^5-3x^2+-1)/(x-1). Find the integral. Divide 8x^5-3x^2-1 by x-1. Resulting polynomial. Expand the integral \int\left(8x^{4}+8x^{3}+8x^{2}+5x+5+\frac{4}{x-1}\right)dx into 6 integrals using the sum rule for integrals, to then solve each integral separately.