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$\int\frac{8a^3-1}{2a-1}da$
Learn how to solve integral calculus problems step by step online. Find the integral of (8a^3-1)/(2a-1). Find the integral. Divide 8a^3-1 by 2a-1. Resulting polynomial. Expand the integral \int\left(4a^{2}+2a+1\right)da into 3 integrals using the sum rule for integrals, to then solve each integral separately.