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$\int\left(\frac{8}{y^2-6y+9}+\frac{4}{y-3}\right)dy$
Learn how to solve problems step by step online. Find the integral of 8/(y^2-6y+9)+4/(y-3). Find the integral. Expand the integral \int\left(\frac{8}{y^2-6y+9}+\frac{4}{y-3}\right)dy into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{8}{y^2-6y+9}dy results in: \frac{-8}{y-3}. The integral \int\frac{4}{y-3}dy results in: 4\ln\left(y-3\right).