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Factor by completing the square $\frac{8}{3}+\frac{2}{7}- \left(\frac{3}{4}-4\right)+6-\frac{1}{3}- \left(9+\frac{5}{7}\right)$

Step-by-step Solution

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Final Answer

$\frac{181}{84}$
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Step-by-step Solution

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Divide $8$ by $3$

$\frac{8}{3}+\frac{2}{7}- \left(\frac{3}{4}-4\right)+6-\frac{1}{3}- \left(9+\frac{5}{7}\right)$

Learn how to solve polynomial factorization problems step by step online.

$\frac{8}{3}+\frac{2}{7}- \left(\frac{3}{4}-4\right)+6-\frac{1}{3}- \left(9+\frac{5}{7}\right)$

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Learn how to solve polynomial factorization problems step by step online. Factor by completing the square 8/3+2/7-(3/4-4)+6-1/3-(9+5/7). Divide 8 by 3. Divide 2 by 7. Divide 3 by 4. Divide -1 by 3.

Final Answer

$\frac{181}{84}$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SimplifyFactorFind the integralFind the derivativeFind 8/3+2/7 using the definitionSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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Function Plot

Plotting: $\frac{181}{84}$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Polynomial Factorization

They are a group of techniques that help us rewrite polynomial expressions as a product of factors.

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