Final answer to the problem
$7x-7+\frac{21x-35}{x^2-x-1}$
Got another answer? Verify it here!
Step-by-step Solution
Specify the solving method
1
Divide $7x^3-14x^2+21x-28$ by $x^2-x-1$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-x\phantom{;}-1;}{\phantom{;}7x\phantom{;}-7\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-x\phantom{;}-1\overline{\smash{)}\phantom{;}7x^{3}-14x^{2}+21x\phantom{;}-28\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-x\phantom{;}-1;}\underline{-7x^{3}+7x^{2}+7x\phantom{;}\phantom{-;x^n}}\\\phantom{-7x^{3}+7x^{2}+7x\phantom{;};}-7x^{2}+28x\phantom{;}-28\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-x\phantom{;}-1-;x^n;}\underline{\phantom{;}7x^{2}-7x\phantom{;}-7\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}7x^{2}-7x\phantom{;}-7\phantom{;}\phantom{;}-;x^n;}\phantom{;}21x\phantom{;}-35\phantom{;}\phantom{;}\\\end{array}$
2
Resulting polynomial
$7x-7+\frac{21x-35}{x^2-x-1}$
Final answer to the problem
$7x-7+\frac{21x-35}{x^2-x-1}$