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Find the break even points of the expression $\frac{4^{\left(x-1\right)}}{2^{\left(x+2\right)}}=246$

Step-by-step Solution

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Final Answer

$x=\log_{2}\left(3936\right)$
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Step-by-step Solution

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Apply the property of the product of two powers of the same base in reverse: $a^{m+n}=a^m\cdot a^n$

$\frac{4^{-1}4^x}{2^2\cdot 2^x}=246$

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$\frac{4^{-1}4^x}{2^2\cdot 2^x}=246$

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Learn how to solve problems step by step online. Find the break even points of the expression (4^(x-1))/(2^(x+2))=246. Apply the property of the product of two powers of the same base in reverse: a^{m+n}=a^m\cdot a^n. Rewrite \frac{4^{-1}4^x}{2^2\cdot 2^x} using the property of the power of a quotient: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. Simplify the fraction \left(\frac{4}{2}\right). The quotient of powers of same base (\frac{4^{-1}2^x}{2^2}) can be rewritten as the base to the power of the difference of the exponents.

Final Answer

$x=\log_{2}\left(3936\right)$

Exact Numeric Answer

$x=11.9425$

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Function Plot

Plotting: $\frac{4^{\left(x-1\right)}}{2^{\left(x+2\right)}}-246$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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