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$\int\frac{3x^8-81}{3x^2+4}dx$
Learn how to solve problems step by step online. Find the integral of (3x^8-81)/(3x^2+4). Find the integral. Divide 3x^8-81 by 3x^2+4. Resulting polynomial. Expand the integral \int\left(x^{6}-\frac{4}{3}x^{4}+\frac{16}{9}x^{2}-\frac{64}{27}+\frac{-1931}{27\left(3x^2+4\right)}\right)dx into 5 integrals using the sum rule for integrals, to then solve each integral separately.