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$\int\frac{3x^4-x^2+1}{x^2-2x-3}dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (3x^4-x^2+1)/(x^2-2x+-3). Find the integral. Divide 3x^4-x^2+1 by x^2-2x-3. Resulting polynomial. Expand the integral \int\left(3x^{2}+6x+20+\frac{58x+61}{x^2-2x-3}\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately.