$\frac{d}{dx}\left(\frac{2x-7}{2x^2-5x+1}\right)=\frac{2\left(2x^2-5x+1\right)+\left(-2x+7\right)\left(4x-5\right)}{\left(2x^2-5x+1\right)^2}$
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Integral
$\int\frac{2x-7}{2x^2-5x+1}dx=-1.0914103\ln\left(-2.2807764+x\right)+1.0914103\ln\left(-\frac{57}{260}+x\right)-\ln\left(\frac{67}{65\sqrt{-\frac{17}{16}+\left(x-\frac{5}{4}\right)^2}}\right)+C_0$
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