Final answer to the problem
$x^2+6x+\frac{-1}{\left(x-1\right)^{2}}+\frac{-8}{x-1}+12\ln\left(x-1\right)+C_0$
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Step-by-step Solution
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1
Find the integral
$\int\frac{2x^4}{x^3-3x^2+3x-1}dx$
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$\int\frac{2x^4}{x^3-3x^2+3x-1}dx$
Learn how to solve problems step by step online. Integrate the function (2x^4)/(x^3-3x^23x+-1). Find the integral. Take out the constant 2 from the integral. Divide x^4 by x^3-3x^2+3x-1. Resulting polynomial.
Final answer to the problem
$x^2+6x+\frac{-1}{\left(x-1\right)^{2}}+\frac{-8}{x-1}+12\ln\left(x-1\right)+C_0$