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Find the break even points of the polynomial $\frac{2x^3+3x^2-1}{x^4+2x^3+2x^2+2x+1}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{2x^3+3x^2-1}{x^4+2x^3+2x^2+2x+1}=0$
Learn how to solve problems step by step online. Find the break even points of the expression (2x^3+3x^2+-1)/(x^4+2x^32x^22x+1). Find the break even points of the polynomial \frac{2x^3+3x^2-1}{x^4+2x^3+2x^2+2x+1} by putting it in the form of an equation and then set it equal to zero. We can factor the polynomial x^4+2x^3+2x^2+2x+1 using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals 1. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial x^4+2x^3+2x^2+2x+1 will then be.