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$\int\frac{2x^2-21x+32}{x^3-8x^2-16x}dx$
Learn how to solve integral calculus problems step by step online. Integrate the function (2x^2-21x+32)/(x^3-8x^2-16x). Find the integral. Rewrite the expression \frac{2x^2-21x+32}{x^3-8x^2-16x} inside the integral in factored form. Rewrite the fraction \frac{2x^2-21x+32}{x\left(x^2-8x-16\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by x\left(x^2-8x-16\right).