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Find the break even points of the polynomial $\frac{2x^2+7x-14}{\left(x^2+1\right)^2\left(x^2+2x-3\right)\left(2x^2+x-3\right)}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{2x^2+7x-14}{\left(x^2+1\right)^2\left(x^2+2x-3\right)\left(2x^2+x-3\right)}=0$
Learn how to solve problems step by step online. Find the break even points of the expression (2x^2+7x+-14)/((x^2+1)^2(x^2+2x+-3)(2x^2+x+-3)). Find the break even points of the polynomial \frac{2x^2+7x-14}{\left(x^2+1\right)^2\left(x^2+2x-3\right)\left(2x^2+x-3\right)} by putting it in the form of an equation and then set it equal to zero. Factor the trinomial \left(2x^2+1x-3\right) of the form ax^2+bx+c, first, make the product of 2 and -3. Now, find two numbers that multiplied give us -6 and add up to 1. Rewrite the original expression.