Final answer to the problem
$\frac{2^{\left(3x+2\right)}+2^{\left(3x+4\right)}+2^{\left(3x+3\right)}}{3^{\left(a^b-2\right)}- 3^{\left(a^b-1\right)}+3^{ab}}$
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Step-by-step Solution
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1
Simplify $\left(3^a\right)^b$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $a$ and $n$ equals $b$
$\frac{2^{\left(3x+2\right)}+2^{\left(3x+4\right)}+2^{\left(3x+3\right)}}{3^{\left(a^b-2\right)}- 3^{\left(a^b-1\right)}+3^{ab}}$
Final answer to the problem
$\frac{2^{\left(3x+2\right)}+2^{\left(3x+4\right)}+2^{\left(3x+3\right)}}{3^{\left(a^b-2\right)}- 3^{\left(a^b-1\right)}+3^{ab}}$