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$\int\frac{16a^2x-25x}{16a^3-7a^2-10a}dx$
Learn how to solve problems step by step online. Integrate the function (16a^2x-25x)/(16a^3-7a^2-10a). Find the integral. Take the constant \frac{1}{16a^3-7a^2-10a} out of the integral. Expand the integral \int\left(16a^2x-25x\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral of a function times a constant (16) is equal to the constant times the integral of the function.