Final answer to the problem
$y=\frac{239}{98},\:y=-\frac{31}{294}$
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Step-by-step Solution
How should I solve this problem?
- Solve for y
- Find the roots
- Solve by factoring
- Solve by completing the square
- Solve by quadratic formula (general formula)
- Find break even points
- Find the discriminant
- Exact Differential Equation
- Linear Differential Equation
- Separable Differential Equation
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1
Subtract the values $\frac{1}{7}$ and $-\frac{2}{5}$
$-\frac{9}{35}+y^2=\frac{7}{3}y$
Learn how to solve integral calculus problems step by step online.
$-\frac{9}{35}+y^2=\frac{7}{3}y$
Learn how to solve integral calculus problems step by step online. Solve the quadratic equation 1/7+y^2+-2/5=7/3y. Subtract the values \frac{1}{7} and -\frac{2}{5}. Divide 7 by 3. Grouping all terms to the left side of the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-\frac{7}{3} and c=-\frac{9}{35}. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.
Final answer to the problem
$y=\frac{239}{98},\:y=-\frac{31}{294}$