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$\int\frac{1}{2\left(s^2-2s+2\right)}ds$
Learn how to solve integral calculus problems step by step online. Find the integral of 1/(2(s^2-2s+2)). Find the integral. Take the constant \frac{1}{2} out of the integral. Solve the integral by applying the formula \displaystyle\int\frac{x'}{x^2+a^2}dx=\frac{1}{a}\arctan\left(\frac{x}{a}\right). Simplify the expression inside the integral.