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Factor the expression $\frac{1}{\sec\left(2x\right)+\tan\left(2x\right)}\left(2\sec\left(2x\right)\tan\left(2x\right)+2\sec\left(2x\right)^2\right)$

Step-by-step Solution

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Final answer to the problem

$2\sec\left(2x\right)$
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Step-by-step Solution

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Multiply the fraction and term

$\frac{2\sec\left(2x\right)\tan\left(2x\right)+2\sec\left(2x\right)^2}{\sec\left(2x\right)+\tan\left(2x\right)}$

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$\frac{2\sec\left(2x\right)\tan\left(2x\right)+2\sec\left(2x\right)^2}{\sec\left(2x\right)+\tan\left(2x\right)}$

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Learn how to solve problems step by step online. Factor the expression 1/(sec(2x)+tan(2x))(2sec(2x)tan(2x)+2sec(2x)^2). Multiply the fraction and term. Factor the polynomial 2\sec\left(2x\right)\tan\left(2x\right)+2\sec\left(2x\right)^2 by it's greatest common factor (GCF): 2\sec\left(2x\right). Simplify the fraction \frac{2\sec\left(2x\right)\left(\tan\left(2x\right)+\sec\left(2x\right)\right)}{\sec\left(2x\right)+\tan\left(2x\right)} by \tan\left(2x\right)+\sec\left(2x\right).

Final answer to the problem

$2\sec\left(2x\right)$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SimplifyFactor by completing the squareFind the integralFind the derivativeFind 1/(sec2x+tan2x)(2sec2x+2sec2x^2) using the definitionSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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Function Plot

Plotting: $2\sec\left(2x\right)$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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