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Find the break even points of the polynomial $\frac{-x^2+2x+3}{3x\left(x-3\right)}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{-x^2+2x+3}{3x\left(x-3\right)}=0$
Learn how to solve problems step by step online. Find the break even points of the expression (-x^2+2x+3)/(3x(x-3)). Find the break even points of the polynomial \frac{-x^2+2x+3}{3x\left(x-3\right)} by putting it in the form of an equation and then set it equal to zero. Factor the trinomial by -1 for an easier handling. Factor the trinomial -\left(x^2-2x-3\right) finding two numbers that multiply to form -3 and added form -2. Thus.