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Find the break even points of the polynomial $\frac{-1}{\frac{x^2+2x+1}{x+1}}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{-1}{\frac{x^2+2x+1}{x+1}}=0$
Learn how to solve problems step by step online. Find the break even points of the expression -1/((x^2+2x+1)/(x+1)). Find the break even points of the polynomial \frac{-1}{\frac{x^2+2x+1}{x+1}} by putting it in the form of an equation and then set it equal to zero. Divide fractions \frac{-1}{\frac{x^2+2x+1}{x+1}} with Keep, Change, Flip: a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}. Multiply both sides of the equation by x^2+2x+1. Multiply both sides of the equation by -1.