Final answer to the problem
Step-by-step Solution
Specify the solving method
Divide fractions $\frac{-1}{\frac{2x^2-x-3}{x^3+2x^2+6x+5}}$ with Keep, Change, Flip: $a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}$
Learn how to solve definition of derivative problems step by step online.
$\frac{-\left(x^3+2x^2+6x+5\right)}{2x^2-x-3}$
Learn how to solve definition of derivative problems step by step online. Factor by completing the square -1/((2x^2-x+-3)/(x^3+2x^26x+5)). Divide fractions \frac{-1}{\frac{2x^2-x-3}{x^3+2x^2+6x+5}} with Keep, Change, Flip: a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (2) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+-\frac{1}{2}xx+\frac{1}{16}.