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Find the derivative of $\frac{\left(x-1\right)^{32}\left(x+1\right)^{\frac{3}{2}}}{\left(x^2+3x+3\right)^{17}}$

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Final Answer

$\frac{\left(32\left(x-1\right)^{31}\sqrt{\left(x+1\right)^{3}}+\frac{3}{2}\left(x-1\right)^{32}\sqrt{x+1}\right)\left(x^2+3x+3\right)^{17}-17\left(x-1\right)^{32}\sqrt{\left(x+1\right)^{3}}\left(x^2+3x+3\right)^{16}\left(2x+3\right)}{\left(x^2+3x+3\right)^{34}}$
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Step-by-step Solution

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Simplifying

$\frac{d}{dx}\left(\frac{\left(x-1\right)^{32}\sqrt{\left(x+1\right)^{3}}}{\left(x^2+3x+3\right)^{17}}\right)$

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$\frac{d}{dx}\left(\frac{\left(x-1\right)^{32}\sqrt{\left(x+1\right)^{3}}}{\left(x^2+3x+3\right)^{17}}\right)$

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Learn how to solve problems step by step online. Find the derivative of ((x-1)^32(x+1)^(3/2))/((x^2+3x+3)^17). Simplifying. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. Simplify \left(\left(x^2+3x+3\right)^{17}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 17 and n equals 2. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=\left(x-1\right)^{32} and g=\sqrt{\left(x+1\right)^{3}}.

Final Answer

$\frac{\left(32\left(x-1\right)^{31}\sqrt{\left(x+1\right)^{3}}+\frac{3}{2}\left(x-1\right)^{32}\sqrt{x+1}\right)\left(x^2+3x+3\right)^{17}-17\left(x-1\right)^{32}\sqrt{\left(x+1\right)^{3}}\left(x^2+3x+3\right)^{16}\left(2x+3\right)}{\left(x^2+3x+3\right)^{34}}$

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Function Plot

Plotting: $\frac{\left(32\left(x-1\right)^{31}\sqrt{\left(x+1\right)^{3}}+\frac{3}{2}\left(x-1\right)^{32}\sqrt{x+1}\right)\left(x^2+3x+3\right)^{17}-17\left(x-1\right)^{32}\sqrt{\left(x+1\right)^{3}}\left(x^2+3x+3\right)^{16}\left(2x+3\right)}{\left(x^2+3x+3\right)^{34}}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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