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Learn how to solve problems step by step online. Integrate the function (3/((x^3-9)(x^3+2x^2-3x)))/(x^2-3x). Find the integral. Rewrite the expression \frac{\frac{3}{\left(x^3-9\right)\left(x^3+2x^2-3x\right)}}{x^2-3x} inside the integral in factored form. Rewrite the fraction \frac{3}{\left(x-\sqrt[3]{9}\right)\left(x^2+\sqrt[3]{9}x+3\sqrt[3]{3}\right)x^2\left(x+3\right)\left(x-1\right)\left(x-3\right)} in 7 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D, F, G, H, I. The first step is to multiply both sides of the equation from the previous step by \left(x-\sqrt[3]{9}\right)\left(x^2+\sqrt[3]{9}x+3\sqrt[3]{3}\right)x^2\left(x+3\right)\left(x-1\right)\left(x-3\right).
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