Final answer to the problem
$\frac{-1}{\left(x^3+2x^2+x\right)\left(x^3+x^2-x-1\right)}$
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Step-by-step Solution
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1
Divide fractions $\frac{\frac{-1}{x^3+2x^2+x}}{x^3+x^2-x-1}$ with Keep, Change, Flip: $\frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}$
$\frac{-1}{\left(x^3+2x^2+x\right)\left(x^3+x^2-x-1\right)}$
Final answer to the problem
$\frac{-1}{\left(x^3+2x^2+x\right)\left(x^3+x^2-x-1\right)}$