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Integrate the function $\frac{\cos\left(x\right)^3-\sin\left(x\right)^3}{\cos\left(x\right)-\sin\left(x\right)}$

Step-by-step Solution

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Final answer to the problem

$x-\frac{1}{4}\cos\left(2x\right)+C_0$
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Step-by-step Solution

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Find the integral

$\int\frac{\cos\left(x\right)^3-\sin\left(x\right)^3}{\cos\left(x\right)-\sin\left(x\right)}dx$

Learn how to solve classify algebraic expressions problems step by step online.

$\int\frac{\cos\left(x\right)^3-\sin\left(x\right)^3}{\cos\left(x\right)-\sin\left(x\right)}dx$

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Learn how to solve classify algebraic expressions problems step by step online. Integrate the function (cos(x)^3-sin(x)^3)/(cos(x)-sin(x)). Find the integral. Rewrite the trigonometric expression \frac{\cos\left(x\right)^3-\sin\left(x\right)^3}{\cos\left(x\right)-\sin\left(x\right)} inside the integral. Expand the integral \int\left(1+\frac{\sin\left(2x\right)}{2}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int1dx results in: x.

Final answer to the problem

$x-\frac{1}{4}\cos\left(2x\right)+C_0$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve integral of ((cosx^3+-1sinx^3)/(cosx+-1sinx))dx using u-substitutionSolve integral of ((cosx^3+-1sinx^3)/(cosx+-1sinx))dx using integration by partsSolve integral of ((cosx^3+-1sinx^3)/(cosx+-1sinx))dx using weierstrass substitution

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Function Plot

Plotting: $x-\frac{1}{4}\cos\left(2x\right)+C_0$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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