Find the limit
$\lim_{x\to-1}\left(\frac{12x^3+12x^2}{x^4-x^2}\right)$
$\lim_{x\to1}\left(\frac{x^3-1}{4x^3-x-3}\right)$
$\lim_{x\to8}\left(\frac{x-8}{x^2-64}\right)$
$\lim_{x\to-3}\left(\frac{x^4-81}{x+3}\right)$
$\lim_{x\to3}\left(\frac{x^3-27}{x^2-9}\right)$
In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value.
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