Find the derivative using logarithmic differentiation method $\frac{d}{dx}\left(\ln\left(\frac{x\sqrt{x^2+1}}{\sqrt[3]{\left(x+9\right)^{2}}}\right)\right)$

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Final answer to the problem

$\frac{1}{x}+\frac{x}{x^2+1}+\frac{-2}{3\left(x+9\right)}$
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Step-by-step Solution

How should I solve this problem?

  • Find the derivative using logarithmic differentiation
  • Find the derivative using the definition
  • Find the derivative using the product rule
  • Find the derivative using the quotient rule
  • Find the derivative
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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1

Simplify the derivative by applying the properties of logarithms

$\frac{d}{dx}\left(\ln\left(x\right)+\frac{1}{2}\ln\left(x^2+1\right)-\frac{2}{3}\ln\left(x+9\right)\right)$

Learn how to solve logarithmic differentiation problems step by step online.

$\frac{d}{dx}\left(\ln\left(x\right)+\frac{1}{2}\ln\left(x^2+1\right)-\frac{2}{3}\ln\left(x+9\right)\right)$

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Learn how to solve logarithmic differentiation problems step by step online. Find the derivative using logarithmic differentiation method d/dx(ln((x(x^2+1)^(1/2))/((x+9)^(2/3)))). Simplify the derivative by applying the properties of logarithms. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function. The derivative of the natural logarithm of a function is equal to the derivative of the function divided by that function. If f(x)=ln\:a (where a is a function of x), then \displaystyle f'(x)=\frac{a'}{a}.

Final answer to the problem

$\frac{1}{x}+\frac{x}{x^2+1}+\frac{-2}{3\left(x+9\right)}$

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Function Plot

Plotting: $\frac{1}{x}+\frac{x}{x^2+1}+\frac{-2}{3\left(x+9\right)}$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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