Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Factor by completing the square
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Find the roots
- Find break even points
- Load more...
To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=30$, $b=13$ and $c=-10$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{-13\pm \sqrt{13^2-4\cdot 30\cdot -10}}{2\cdot 30}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 30x^2+13x+-10=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=30, b=13 and c=-10. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 37 and -13.