Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Factor by completing the square
- Product of Binomials with Common Term
- FOIL Method
- Find the integral
- Find the derivative
- Factor
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
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The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: $(a+b)^3=a^3+3a^2b+3ab^2+b^3 = (\sin\left(i\right))^3+3(\sin\left(i\right))^2(i\sin\left(i\right))+3(\sin\left(i\right))(i\sin\left(i\right))^2+(i\sin\left(i\right))^3 =$
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$\sin\left(i\right)^3+3i\sin\left(i\right)^2\sin\left(i\right)+3\sin\left(i\right)\left(i\sin\left(i\right)\right)^2+\left(i\sin\left(i\right)\right)^3$
Learn how to solve problems step by step online. Expand and simplify the trigonometric expression (sin(i)+isin(i))^3. The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: (a+b)^3=a^3+3a^2b+3ab^2+b^3 = (\sin\left(i\right))^3+3(\sin\left(i\right))^2(i\sin\left(i\right))+3(\sin\left(i\right))(i\sin\left(i\right))^2+(i\sin\left(i\right))^3 =. When multiplying exponents with same base you can add the exponents: 3i\sin\left(i\right)^2\sin\left(i\right). The power of a product is equal to the product of it's factors raised to the same power. Applying the property of complex numbers: i^2=-1.
