Factor by completing the square $\frac{x^6+y^6}{x^2+y^2}$

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Final answer to the problem

$x^{4}-x^{2}y^{2}+y^{4}$
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Step-by-step Solution

How should I solve this problem?

  • Factor by completing the square
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Prove from LHS (left-hand side)
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Factor the sum or difference of cubes using the formula: $a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2)$

$\frac{\left(\sqrt[3]{x^6}+\sqrt[3]{y^6}\right)\left(\sqrt[3]{\left(x^6\right)^{2}}-\sqrt[3]{x^6}\sqrt[3]{y^6}+\sqrt[3]{\left(y^6\right)^{2}}\right)}{x^2+y^2}$

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$\frac{\left(\sqrt[3]{x^6}+\sqrt[3]{y^6}\right)\left(\sqrt[3]{\left(x^6\right)^{2}}-\sqrt[3]{x^6}\sqrt[3]{y^6}+\sqrt[3]{\left(y^6\right)^{2}}\right)}{x^2+y^2}$

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Learn how to solve problems step by step online. Factor by completing the square (x^6+y^6)/(x^2+y^2). Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). Simplify \sqrt[3]{x^6} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 6 and n equals \frac{1}{3}. Multiply the fraction and term in 6\cdot \left(\frac{1}{3}\right). Divide 6 by 3.

Final answer to the problem

$x^{4}-x^{2}y^{2}+y^{4}$

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Plotting: $x^{4}-x^{2}y^{2}+y^{4}$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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