Final answer to the problem
$\frac{\left(x-\frac{3}{2}\right)^2-\frac{37}{4}}{\left(x+1\right)^2\left(2x+3\right)}$
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Step-by-step Solution
How should I solve this problem?
- Factor by completing the square
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Add and subtract $\displaystyle\left(\frac{b}{2a}\right)^2$
$\frac{x^2-3x-7+{\left(\left(-\frac{3}{2}\right)\right)}^2- {\left(\left(-\frac{3}{2}\right)\right)}^2}{\left(x+1\right)^2\left(2x+3\right)}$
Learn how to solve polynomial factorization problems step by step online.
$\frac{x^2-3x-7+{\left(\left(-\frac{3}{2}\right)\right)}^2- {\left(\left(-\frac{3}{2}\right)\right)}^2}{\left(x+1\right)^2\left(2x+3\right)}$
Learn how to solve polynomial factorization problems step by step online. Factor by completing the square (x^2-3x+-7)/((x+1)^2(2x+3)). Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Calculate the power {\left(\left(-\frac{3}{2}\right)\right)}^2. Multiply the fraction and term in - \frac{9}{4}. Simplify the addition \left(x- \frac{3}{2}\right)^2-7-\frac{9}{4}.
Final answer to the problem
$\frac{\left(x-\frac{3}{2}\right)^2-\frac{37}{4}}{\left(x+1\right)^2\left(2x+3\right)}$
