Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Integrate using trigonometric identities
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using basic integrals
- Product of Binomials with Common Term
- FOIL Method
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$\int\left(\left(3-x\right)^2-\left(x-3\right)\left(7x+4\right)-18+2x^2\right)dx$
Learn how to solve integral calculus problems step by step online. Integrate the function (3-x)^2-(x-3)(7x+4)+-182x^2. Find the integral. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Multiplying polynomials -1 and x-3. Multiply the single term 7x+4 by each term of the polynomial \left(-x+3\right).