Final answer to the problem
$234$
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Step-by-step Solution
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- Integrate using trigonometric identities
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using basic integrals
- Product of Binomials with Common Term
- FOIL Method
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1
Expand the integral $\int_{1}^{3}\left(8x^3+6x^2+4x+3\right)dx$ into $4$ integrals using the sum rule for integrals, to then solve each integral separately
$\int_{1}^{3}8x^3dx+\int_{1}^{3}6x^2dx+\int_{1}^{3}4xdx+\int_{1}^{3}3dx$
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$\int_{1}^{3}8x^3dx+\int_{1}^{3}6x^2dx+\int_{1}^{3}4xdx+\int_{1}^{3}3dx$
Learn how to solve problems step by step online. Integrate the function 8x^3+6x^24x+3 from 1 to 3. Expand the integral \int_{1}^{3}\left(8x^3+6x^2+4x+3\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{1}^{3}8x^3dx results in: 160. The integral \int_{1}^{3}6x^2dx results in: 52. The integral \int_{1}^{3}4xdx results in: 16.
Final answer to the problem
$234$
