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Find the break even points of the expression $x^2+16x+55=0$

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Solution

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Final answer to the problem

$x=-11$
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Step-by-step Solution

How should I solve this problem?

  • Find break even points
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Load more...
Can't find a method? Tell us so we can add it.
1

Factor the trinomial $x^2+16x+55$ finding two numbers that multiply to form $55$ and added form $16$

$\begin{matrix}\left(5\right)\left(11\right)=55\\ \left(5\right)+\left(11\right)=16\end{matrix}$

Learn how to solve classify algebraic expressions problems step by step online.

$\begin{matrix}\left(5\right)\left(11\right)=55\\ \left(5\right)+\left(11\right)=16\end{matrix}$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression x^2+16x+55=0. Factor the trinomial x^2+16x+55 finding two numbers that multiply to form 55 and added form 16. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Break the equation in 2 factors and set each factor equal to zero, to obtain simpler equations. Solve the equation (1).

Final answer to the problem

$x=-11$

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Function Plot

Plotting: $x^2+16x+55$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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