Find the break even points of the expression $2\ln\left(20\cdot \left(\frac{201168}{125}\right)\right)+2412\ln\left(20\right)-\frac{551}{20}$

Step-by-step Solution

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Final answer to the problem

$2\ln\left(\frac{804672}{25}\right)+2412\ln\left(20\right)-\frac{551}{20}$
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Step-by-step Solution

How should I solve this problem?

  • Find break even points
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Find the discriminant
  • Load more...
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1

Multiply the fraction and term in $20\cdot \left(\frac{201168}{125}\right)$

$2\ln\left(\frac{20\cdot 201168}{125}\right)+2412\ln\left(20\right)-\frac{551}{20}$

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$2\ln\left(\frac{20\cdot 201168}{125}\right)+2412\ln\left(20\right)-\frac{551}{20}$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression 2ln(20201168/125)+2412ln(20)-551/20. Multiply the fraction and term in 20\cdot \left(\frac{201168}{125}\right). Multiply 20 times 201168. Divide 4023360 by 125.

Final answer to the problem

$2\ln\left(\frac{804672}{25}\right)+2412\ln\left(20\right)-\frac{551}{20}$

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Function Plot

Plotting: $2\ln\left(\frac{804672}{25}\right)+2412\ln\left(20\right)-\frac{551}{20}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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