Find the break even points of the expression $\frac{1}{3}\left(5x-2\right)-\frac{1}{4}=\frac{3x}{2}+\frac{1}{4}$

Step-by-step Solution

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Final answer to the problem

$x=7$
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Step-by-step Solution

How should I solve this problem?

  • Find break even points
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Load more...
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Solve the product $\frac{1}{3}\left(5x-2\right)$

$\frac{5}{3}x-\frac{2}{3}-\frac{1}{4}=\frac{3x}{2}+\frac{1}{4}$

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$\frac{5}{3}x-\frac{2}{3}-\frac{1}{4}=\frac{3x}{2}+\frac{1}{4}$

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Unlock the first 3 steps of this solution

Learn how to solve problems step by step online. Find the break even points of the expression (5x-2)1/3-1/4=(3x)/2+1/4. Solve the product \frac{1}{3}\left(5x-2\right). Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Multiply the fraction and term in - -\frac{2}{3}. Multiply the fraction and term in - -\frac{1}{4}.

Final answer to the problem

$x=7$

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Function Plot

Plotting: $\frac{1}{3}\left(5x-2\right)-\frac{1}{4}+\frac{-3x}{2}-\frac{1}{4}$

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Got a different answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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