Find the break even points of the expression $120\cdot -ex+14ex$

Step-by-step Solution

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Final answer to the problem

$x=0$
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Step-by-step Solution

How should I solve this problem?

  • Find break even points
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Load more...
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Find the break even points of the polynomial $120\cdot -ex+14ex$ by putting it in the form of an equation and then set it equal to zero

$120\cdot -ex+14ex=0$

Learn how to solve classify algebraic expressions problems step by step online.

$120\cdot -ex+14ex=0$

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Unlock the first 3 steps of this solution

Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression 120*-ex+14*ex. Find the break even points of the polynomial 120\cdot -ex+14ex by putting it in the form of an equation and then set it equal to zero. Combining like terms 120\cdot -ex and 14ex. Divide both sides of the equation by 134. Simplify the fraction \frac{134x}{134} by 134.

Final answer to the problem

$x=0$

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Function Plot

Plotting: $120\cdot -ex+14ex$

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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