Find the break even points of the expression $\frac{x^4-4x^3-4x^2}{-x+\frac{-x^2}{2}+\frac{-x^3}{3}+\frac{-x^4}{4}+\frac{-x^5}{5}}$

Step-by-step Solution

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Final answer to the problem

$x=0,\:x=\frac{4+\sqrt{32}}{2},\:x=\frac{4-\sqrt{32}}{2}$
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Step-by-step Solution

How should I solve this problem?

  • Find break even points
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Load more...
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Find the break even points of the polynomial $\frac{x^4-4x^3-4x^2}{-x+\frac{-x^2}{2}+\frac{-x^3}{3}+\frac{-x^4}{4}+\frac{-x^5}{5}}$ by putting it in the form of an equation and then set it equal to zero

$\frac{x^4-4x^3-4x^2}{-x+\frac{-x^2}{2}+\frac{-x^3}{3}+\frac{-x^4}{4}+\frac{-x^5}{5}}=0$

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$\frac{x^4-4x^3-4x^2}{-x+\frac{-x^2}{2}+\frac{-x^3}{3}+\frac{-x^4}{4}+\frac{-x^5}{5}}=0$

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Learn how to solve problems step by step online. Find the break even points of the expression (x^4-4x^3-4x^2)/(-x+(-x^2)/2(-x^3)/3(-x^4)/4(-x^5)/5). Find the break even points of the polynomial \frac{x^4-4x^3-4x^2}{-x+\frac{-x^2}{2}+\frac{-x^3}{3}+\frac{-x^4}{4}+\frac{-x^5}{5}} by putting it in the form of an equation and then set it equal to zero. Factor the polynomial x^4-4x^3-4x^2 by it's greatest common factor (GCF): x^2. Multiply both sides of the equation by -x+\frac{-x^2}{2}+\frac{-x^3}{3}+\frac{-x^4}{4}+\frac{-x^5}{5}. Any expression multiplied by 0 is equal to 0.

Final answer to the problem

$x=0,\:x=\frac{4+\sqrt{32}}{2},\:x=\frac{4-\sqrt{32}}{2}$

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Function Plot

Plotting: $\frac{x^4-4x^3-4x^2}{-x+\frac{-x^2}{2}+\frac{-x^3}{3}+\frac{-x^4}{4}+\frac{-x^5}{5}}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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