Find the break even points of the expression $\frac{1}{x^2+x-12}+\frac{-2}{x^2-16}=0$

Step-by-step Solution

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Final answer to the problem

$x=2$
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Step-by-step Solution

How should I solve this problem?

  • Find break even points
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Load more...
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1

Factor the trinomial $x^2+x-12$ finding two numbers that multiply to form $-12$ and added form $1$

$\begin{matrix}\left(-3\right)\left(4\right)=-12\\ \left(-3\right)+\left(4\right)=1\end{matrix}$

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$\begin{matrix}\left(-3\right)\left(4\right)=-12\\ \left(-3\right)+\left(4\right)=1\end{matrix}$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression 1/(x^2+x+-12)+-2/(x^2-16)=0. Factor the trinomial x^2+x-12 finding two numbers that multiply to form -12 and added form 1. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Factor the difference of squares x^2-16 as the product of two conjugated binomials. The least common multiple (LCM) of a sum of algebraic fractions consists of the product of the common factors with the greatest exponent, and the uncommon factors.

Final answer to the problem

$x=2$

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Function Plot

Plotting: $\frac{1}{x^2+x-12}+\frac{-2}{x^2-16}$

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3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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