Final answer to the problem
$y=4,\:y=8$
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Step-by-step Solution
How should I solve this problem?
- Solve by completing the square
- Solve for y
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Load more...
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1
Factor the trinomial $y^2-12y+32$ finding two numbers that multiply to form $32$ and added form $-12$
$\begin{matrix}\left(-4\right)\left(-8\right)=32\\ \left(-4\right)+\left(-8\right)=-12\end{matrix}$
Learn how to solve quadratic equations problems step by step online.
$\begin{matrix}\left(-4\right)\left(-8\right)=32\\ \left(-4\right)+\left(-8\right)=-12\end{matrix}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation y^2-12y+32=0. Factor the trinomial y^2-12y+32 finding two numbers that multiply to form 32 and added form -12. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Break the equation in 2 factors and set each factor equal to zero, to obtain simpler equations. Solve the equation (1).
Final answer to the problem
$y=4,\:y=8$
